Notation compacte
Durée : 15 mn
Note maximale : 16
Question
On considère les atomes suivants :
\(\textrm{K}\),\(\textrm{Re}\),\(\textrm{Mn}\),\(\textrm{Fe}\),\(\textrm{Cu}\),\(\textrm{Ag}\),\(\textrm{Cd}\),\(\textrm{Ba}\),\(\textrm{Ga}\),\(\textrm{N}\),\(\textrm{P}\),\(\textrm{As}\),\(\textrm{Sb}\),\(\textrm{F}\),\(\textrm{Br}\),\(\textrm{I}\)
Ecrire la forme compacte de la configuration de l'état fondamental.
Classification périodique avec symbole des éléments et numéro atomique
Solution
\(\textrm{K}\): Z = 19 = 18+1 \((\textrm{Ar})~4\textrm{s}^{2}\)
\(\textrm{Re}\): Z = 75 = 54+21 \((\textrm{Xe})~4\textrm{f}^{14}~5\textrm{d}^{5}~6\textrm{s}^{2}\)
\(\textrm{Mn}\): Z = 25 = 18+7 \((\textrm{Ar})~3\textrm{d}^{5}~4\textrm{s}^{2}\)
\(\textrm{Fe}\): Z = 26 = 18+8 \((\textrm{Ar})~3\textrm{d}^{6}~4\textrm{s}^{2}\)
\(\textrm{Cu}\): Z = 29 = 18+11 \((\textrm{Ar})~3\textrm{d}^{10}~4\textrm{s}^{2}\)Exception
\(\textrm{Ag}\): Z = 47 = 36+11 \((\textrm{Kr})~3\textrm{d}^{10}~5\textrm{s}^{2}\)
\(\textrm{Cd}\): Z = 48 = 36+12 \((\textrm{Kr})~3\textrm{d}^{10}~5\textrm{s}^{2}\)
\(\textrm{Ba}\): Z = 56 = 54+2 \((\textrm{Xe})~6\textrm{s}^{2}\)
\(\textrm{Ga}\): Z = 31 = 18+13 \((\textrm{Ar})~3\textrm{d}^{10}~4\textrm{s}^{2}~4\textrm{p}^{1}\)
\(\textrm{N}\): Z = 7 = 2+5 \((\textrm{He})~2\textrm{s}^{2}~2\textrm{p}^{3}\)
\(\textrm{P}\): Z = 15 = 10+5 \((\textrm{Ne})~3\textrm{s}^{2}~3\textrm{p}^{3}\)
\(\textrm{As}\): Z = 33 = 18+15 \((\textrm{Ar})~3\textrm{d}^{10}~4\textrm{s}^{2}~4\textrm{p}^{3}\)
\(\textrm{Sb}\): Z = 51 = 36+15 \((\textrm{Kr})~4\textrm{d}^{10}~5\textrm{s}^{2}~5\textrm{p}^{3}\)
\(\textrm{F}\): Z = 9 = 2+7 \((\textrm{Ar})~2\textrm{s}^{2}~2\textrm{p}^{5}\)
\(\textrm{Br}\): Z = 35 = 18+17 \((\textrm{Ar})~3\textrm{d}^{10}~4\textrm{s}^{2}~4\textrm{p}^{5}\)
\(\textrm{I}\): Z = 53 = 36+17 \((\textrm{Kr})~4\textrm{d}^{10}~5\textrm{s}^{2}~5\textrm{p}^{5}\)